$3-8\left(x+1\right)^2-10\left(x+1\right)=0$
$-4\left(1-5\right)-\left(4^2\right)$
$tan\left(\theta+\frac{\pi}{4}\right)=\frac{tan\theta\:+1}{1-tan\theta\:}$
$\left(x^2\cdot\frac{1}{x}\right)\left(x\right)$
$4cos^2a=1$
$a\left(18a^4-32\right)$
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