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p= 3x3−1,4x +6yq = x2 − o,3xp=\:3x^3-1,4x\:+6yq\:=\:x^2\:-\:o,3x

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Final answer to the exercise

p=3x3−1.4x+6yq3+x2−o,3x3=0, (p=3x3−1.4x+6yq)23−p=3x3−1.4x+6yq3x2−o,3x3+(x2−o,3x)23=0\sqrt[3]{p=3x^3-1.4x+6yq}+\sqrt[3]{x^2-o,3x}=0,\:\sqrt[3]{\left(p=3x^3-1.4x+6yq\right)^{2}}-\sqrt[3]{p=3x^3-1.4x+6yq}\sqrt[3]{x^2-o,3x}+\sqrt[3]{\left(x^2-o,3x\right)^{2}}=0

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p= 3x3−1,4x +6yq = x2 − o,3x
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