$2x+4=10$
$2y^2-5y-6;\:y=-2$
$\left(4x^3-6x+2\right)\cdot\left(4x^2+3\right)$
$\int x\left(x^2+6\right)^{-3}dx$
$\left(-892\right)-674$
$\left(x^4-x^2+3\right)\left(2x^4+3x^2-5\right)$
$\frac{9^2}{4}+ab+b^2$
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