$\lim_{x\to\infty}\left(x-ln\left(e^x+1\right)\right)$
$-\frac{\left(2u-1\right)}{4u}$
$4y'-6e^xy=0$
$3-2x=-1.5$
$6^2:\:4+3\cdot9-3$
$\left(-2x-6y+3z\right)+\left(x+5y-8z\right)+\left(x+y-z\right)$
$17+\frac{-18}{6}$
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