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Solving: (cos⁡(35)−1+sin⁡(−25)−1)sin⁡()\left(\cos\left(\frac{3}{5}\right)^{-1}+\sin\left(-\frac{2}{5}\right)^{-1}\right)\sin\left(\right)
Solve instead: sin[cos−1(35)+sin−1(−25)]sin\left[cos^{-1}\left(\frac{3}{5}\right)+sin^{-1}\left(-\frac{2}{5}\right)\right]

Exercise

sin[cos−1(35)+sin−1(−25)]sin\left[cos^{-1}\left(\frac{3}{5}\right)+sin^{-1}\left(-\frac{2}{5}\right)\right]

Step-by-step Solution

1

Multiply the single term sin⁡()\sin\left(\right) by each term of the polynomial (cos⁡(35)−1+sin⁡(−25)−1)\left(\cos\left(\frac{3}{5}\right)^{-1}+\sin\left(-\frac{2}{5}\right)^{-1}\right)

cos⁡(35)−1sin⁡()+sin⁡(−25)−1sin⁡()\cos\left(\frac{3}{5}\right)^{-1}\sin\left(\right)+\sin\left(-\frac{2}{5}\right)^{-1}\sin\left(\right)

Final answer to the exercise

cos⁡(35)−1sin⁡()+sin⁡(−25)−1sin⁡()\cos\left(\frac{3}{5}\right)^{-1}\sin\left(\right)+\sin\left(-\frac{2}{5}\right)^{-1}\sin\left(\right)

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sin[cos−1(35 )+sin−1(−25 )]
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