$6\left(-5x\:-\:9\right)=-204$
$x^2-2x+1=16$
$\frac{\left(3x^2+x\right)}{-x^2+3x-3}$
$\lim_{x\to0}\left(\frac{\left(x+1\right)}{2x}\right)$
$\left(x+6\right)\left(-8\right)$
$1728b^3+1728y^3$
$1+cos\left(-x\right)$
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