$f\:\left(y\right)=\frac{\left(1+x\right)^3\sqrt[4]{x-1}}{\sqrt[5]{\left(x-3\right)}^2}$

$\left(6x+y^2\right)^3$

$\int\frac{x^2+4}{x\left(x^2+1\right)\left(x-1\right)}dx$

$-\left(4x+1\right)^2$

$\int\sqrt[3]{x^2}-\left(x+3\right)^2dx$

$\lim_{x\to0}\left(\frac{xe^{2x}-ln\left(11+x\right)}{13x^2}\right)$