(−8x3+24x2−42x+16)(4x−2)\left(-8x^3+24x^2-42x+16\right)\left(4x-2\right)(−8x3+24x2−42x+16)(4x−2)
limx→∞(ln(x+1x+2))\lim_{x\to\infty}\left(\ln\left(\frac{x+1}{x+2}\right)\right)x→∞lim(ln(x+2x+1))
0,09x6+1−0,6x30,09x^{6}+1-0,6x^{3}0,09x6+1−0,6x3
limx→∞(ln(3x+4)ln(5x+8)+7)\lim_{x\to\infty}\left(\frac{ln\left(3x+4\right)}{ln\left(5x+8\right)+7}\right)x→∞lim(ln(5x+8)+7ln(3x+4))
x3−2xx3+3x+2\frac{x^3-2x}{x^3+3x+2}x3+3x+2x3−2x
x2y′=xyx^2y'=xyx2y′=xy
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