$3+x+3y+1-4x+x-5$
$\left(2\sqrt[3]{3}\right)^3\:$
$\frac{2x^2+11x+16}{x+3}$
$a^2+2a-37=0$
$3m+4y+4m+4m$
$z^1^0^1+z^1$
$\left(x+2\right)^2+\left(x-2\right)^2+\left(x+3\right)^2-\left(x-3\right)^2$
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