Solve the differential equation $x\frac{dy}{dx}+1=x+y$

Step-by-step Solution

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sin
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asin
acos
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sinh
cosh
tanh
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csch

asinh
acosh
atanh
acoth
asech
acsch

Final answer to the problem

$y=\left(\ln\left(x\right)+\frac{1}{x}+C_0\right)x$
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Step-by-step Solution

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  • Exact Differential Equation
  • Linear Differential Equation
  • Separable Differential Equation
  • Homogeneous Differential Equation
  • Integrate by partial fractions
  • Product of Binomials with Common Term
  • FOIL Method
  • Integrate by substitution
  • Integrate by parts
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1

Rewrite the differential equation in standard form

Learn how to solve integrals of polynomial functions problems step by step online.

$\frac{dy}{dx}+\frac{1}{x}=\frac{x+y}{x}$

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Unlock the first 3 steps of this solution

Learn how to solve integrals of polynomial functions problems step by step online. Solve the differential equation xdy/dx+1=x+y. Rewrite the differential equation in standard form. We need to isolate the dependent variable y, we can do that by simultaneously subtracting \frac{1}{x} from both sides of the equation. Multiplying the fraction by -1. Combine fractions with common denominator x.

Final answer to the problem

$y=\left(\ln\left(x\right)+\frac{1}{x}+C_0\right)x$

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Function Plot

Plotting: $x\frac{dy}{dx}+1-x-y$

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Go!
1
2
3
4
5
6
7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

How to improve your answer:

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