−16−1+15−5(3)-16-1+15-5\left(3\right)−16−1+15−5(3)
∫3∞(1xln(x))dx\int_3^{\infty}\left(\frac{1}{x\ln\left(x\right)}\right)dx∫3∞(xln(x)1)dx
x+1≤3x−4x+1\le3x-4x+1≤3x−4
limx→0(x3−2x2+13x2−6x)\lim_{x\to0}\left(\frac{x^3-2x^2+1}{3x^2-6x}\right)x→0lim(3x2−6xx3−2x2+1)
dydx=yx6yx2\frac{dy}{dx}=yx6yx^2dxdy=yx6yx2
dydx+yx=exx\frac{dy}{dx}+\frac{y}{x}=\frac{e^x}{x}dxdy+xy=xex
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