$6^2+12\cdot3-\frac{300}{\left(54-24\right)}+56-14$
$5-2x=15$
$\int\frac{1+x^2+x^3}{x\left(3x+2\right)}dx$
$\:\lim\:_{x\to\:\:3}\left(\frac{x^3-3x^2+2x-6}{2x-4}\right)$
$\frac{dy}{dt}=t^2\left(y^2-5y+4\right)$
$46r-28=71r-78$
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