$-10x^2+490-x$
$\frac{a^6+a^4-8a^2+4a+2}{a+3}$
$\left(\frac{2}{1-sin\left(x\right)}\right)+\left(\frac{2}{1+sin\left(x\right)}\right)$
$\frac{\frac{1}{25}}{\frac{1}{125}}$
$xy-x-10y;\:x=0;\:y=-1$
$13r+5s-2r$
$x^2e^2x$
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