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Moving the term $-6$ to the other side of the inequation with opposite sign
Learn how to solve definite integrals problems step by step online.
$x^2-5x>0+6$
Learn how to solve definite integrals problems step by step online. Solve the inequality x^2-5x+-6>0. Moving the term -6 to the other side of the inequation with opposite sign. Add the values 0 and 6. Factor the polynomial x^2-5x. Add and subtract \left(\frac{b}{2}\right)^2, replacing b by it's value -5. Now, we can factor x^2+-5x+\frac{25}{4} as a squared binomial of the form \left(x+\frac{b}{2}\right)^2.