$\frac{1-3x\left(2x^2+3x-5\right)}{x-1}$
$b^2-2bc+c^2$
$\frac{x^{3+1}}{x^2-9}$
$6c\:+\:7\:+\:4c\:=\:-33\:$
$16x^2\cdot\sin\left(x\right)+4x^4\cdot\cos\left(x\right)$
$0-\left(-2\right)$
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