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$xy+y=y^2$
$2<-8-u$
$3x\left(3x+8z\right)-8z\left(3x+8z\right)$
$\frac{\left(2x^4-5x^3+x^2\right)}{\left(x-1\right)}$
$\frac{x}{3-x}<2$
$\frac{du}{dx}=u^2$
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