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Exercise

$x^3+y^3-2=0$

Step-by-step Solution

1

We need to isolate the dependent variable $y$, we can do that by simultaneously subtracting $x^3-2$ from both sides of the equation

$y^3=-\left(x^3-2\right)$
2

Simplify the product $-(x^3-2)$

$y^3=-x^3+2$
3

Removing the variable's exponent raising both sides of the equation to the power of $\frac{1}{3}$

$\sqrt[3]{y^3}=\sqrt[3]{-x^3+2}$
4

Cancel exponents $3$ and $1$

$y=\sqrt[3]{-x^3+2}$

Final answer to the exercise

$y=\sqrt[3]{-x^3+2}$

Try other ways to solve this exercise

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  • Solve by quadratic formula (general formula)
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Similar Questions Solved

$\log_3\left(81\right)=4$

Main Topic: Equations

In mathematics, an equation is a statement of an equality containing one or more variables. Solving the equation consists of determining which values of the variables make the equality true. In this situation, variables are also known as unknowns and the values which satisfy the equality are known as solutions.

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