$\left(2x+3y+10\right)^2$
$2c-5=6+c$
$\left(8x^2y-3xy-6xy^2\right)+\left(3x^2y-12xy\right)$
$-71=\frac{x}{64}$
$-\left(2.4f+g\right)-6\ $
$\cos\:\left(x\right)+\frac{4}{cos\left(x\right)}=8cos\left(x\right)+4cos\left(x\right)tan^2\left(x\right)$
$\frac{2}{x}+\frac{2}{x}$
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