$x^2-24x+144$
$16x^2-40x+25$
$x^2+22x+121$
$4x^4-29x^2+25$
$m^2+4mn+4n^2$
$x^2+x+\frac{1}{4}$
Given a function f(x) and the interval [a,b], the definite integral is equal to the area that is bounded by the graph of f(x), the x-axis and the vertical lines x=a and x=b
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