$2x\sqrt[n]{4^{n+2}}x\sqrt[n]{2^{n-4}}$
$\lim_{x\to0}\:\left(x^2+x\right)^{\frac{1}{\ln\left(x\right)}}$
$4-x\le5x+8$
$x+4x+9$
$\int\frac{\left(12\right)\left(6^{\sqrt{5x}}\right)}{\sqrt{5x}}dx$
$\frac{x^2+5x+1}{x+3}$
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