$\left(n+3\right)^2-\left(n-3\right)^2$

$\left(x^3+x+1\right)\left(2x+3\right)$

$8\left(\frac{3}{4}\right)^3-17\left(\frac{3}{4}\right)^2+12\left(\frac{3}{4}\right)+14$

$25u^2-90u+81$

$\frac{33-22x+7x^3+6x^4}{6x^2+x-2}$

$\log_{64}\left(7t-5\right)=\frac{1}{6}$

$\left(3x+8\right)-6\left(2.5x-3\right)$