$x^3+3x-x+3$
$\frac{64x^6-125}{4x^2-5}$
$\left(-2.^3\right).\left(-5.\right).\left(-3.^2\right)$
$v^2-3v^2+3v-1$
$-x-10x$
$\lim_{x\to\infty}\left(\frac{3x^2+11x+10}{4e^{2x+1}}\right)$
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