Exercise
$y=\frac{3\left(x+2\right)^2}{x^3+4x^2+x-6}$
Step-by-step Solution
Learn how to solve inequalities problems step by step online. Solve the rational equation y=(3(x+2)^2)/(x^3+4x^2x+-6). We can factor the polynomial x^3+4x^2+x-6 using the rational root theorem, which guarantees that for a polynomial of the form a_nx^n+a_{n-1}x^{n-1}+\dots+a_0 there is a rational root of the form \pm\frac{p}{q}, where p belongs to the divisors of the constant term a_0, and q belongs to the divisors of the leading coefficient a_n. List all divisors p of the constant term a_0, which equals -6. Next, list all divisors of the leading coefficient a_n, which equals 1. The possible roots \pm\frac{p}{q} of the polynomial x^3+4x^2+x-6 will then be. Trying all possible roots, we found that -3 is a root of the polynomial. When we evaluate it in the polynomial, it gives us 0 as a result.
Solve the rational equation y=(3(x+2)^2)/(x^3+4x^2x+-6)
Final answer to the exercise
$y=\frac{3\left(x+2\right)}{\left(x-1\right)\left(x+3\right)}$