$26h+2+-11h-6$
$\int\frac{11}{x^2-25}dx$
$10a^2+7a-12$
$\int\left(4x^2+3\right)^{-6}xdx$
$\sin\left(\frac{3}{10}\right)^2\cdot\cos\left(x\right)^2=1$
$\frac{\left(2xy\right)^{\frac{4}{3}}}{\left(9x\right)^{\frac{4}{3}}}$
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