Exercise
$y^2-2y-8=0$
Step-by-step Solution
Learn how to solve problems step by step online. Solve the quadratic equation y^2-2y+-8=0. Factor the trinomial y^2-2y-8 finding two numbers that multiply to form -8 and added form -2. Rewrite the polynomial as the product of two binomials consisting of the sum of the variable and the found values. Break the equation in 2 factors and set each factor equal to zero, to obtain simpler equations. Solve the equation (1).
Solve the quadratic equation y^2-2y+-8=0
Final answer to the exercise
$y=-2,\:y=4$