$\sqrt{x^2}+4x+4$
$7+\left(-2-\left(-5+8\right)\right)$
$6xy^2+12xy+7xz$
$\left(-7x+3\right)\cdot\left(-5x^2\right)$
$y^2-6y+1$
$y=\left(x^3-2x\right)^2y\left(3\right)$
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