$\left(2x^2+4\right)\left(2x^2-8\right)$
$2x^2y+x^2y^2+x^2y$
$\lim_{x\to+\infty}\frac{x+4}{3x^2-5}$
$\int_0^{4.2}\left(\sqrt{1+\tan\left(\frac{\pi\cdot x}{16.4}\right)^2}\right)dx$
$\sqrt[6]{8x^3}$
$9+3g=15$
$-2wc^2-4\left(wc-wc^2\right)-2c\left(6-w\right)-9w+20c$
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