$\int\left(\frac{x^{-4}}{5}\right)dx$
$\frac{d}{dx}\left(y=\left(7x+\frac{9}{x}\right)^{-3}\right)$
$\frac{2x+1}{-4x+8}$
$x^3y^2-x^4y-x^3y$
$s^7t^6u^{-1}\:x\:s^0t^4u^{-1}$
$7x+9y=-42$
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