Final answer to the problem
$\left(y-3\right)\left(y^2+3y+9\right)$
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Step-by-step Solution
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- Integrate by partial fractions
- Product of Binomials with Common Term
- FOIL Method
- Integrate by substitution
- Integrate by parts
- Integrate using tabular integration
- Integrate by trigonometric substitution
- Weierstrass Substitution
- Prove from LHS (left-hand side)
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1
Factor the difference of cubes: $a^3-b^3 = (a-b)(a^2+ab+b^2)$
$\left(y-3\right)\left(y^2+3y+9\right)$
Final answer to the problem
$\left(y-3\right)\left(y^2+3y+9\right)$
