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Binomial Conjugates


Definition

In algebra, a conjugate is a binomial formed by negating the second term of a binomial.

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Problems Solved

$y=x\left(2x-3\right)\left(2x+3\right)$
$f\left(x\right)=\frac{-1}{\left(1-x\right)\left(x+1\right)}$
$y=\left(\sin\left(x\right)+\cos\left(x\right)\right)\left(\cos\left(x\right)-\sin\left(x\right)\right)$
$h\left(x\right)=\frac{7x^3+9}{x^4-2}$
$f\left(x\right)=\left(senx-cosx\right)\left(senx+cosx\right)+2cos2x$
$f\left(x\right)=\left(senx-cosx\right)\left(senx+cosx\right)+2cos^2x$
$F\left(X\right)=\left(4X+2\right)\left(4X-2\right)$
$f\left(x\right)=\left(x^4+1\right)\left(x^4-1\right)$

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Popular problems

$y=\left(\frac{\left(t+1\right)\left(t-1\right)}{\left(t-2\right)\left(t+3\right)}\right)^5$ 3 views
$F\left(X\right)=\left(4X+2\right)\left(4X-2\right)$ 2 views
$f\left(x\right)=\left(x^4+1\right)\left(x^4-1\right)$
$f\left(x\right)=\frac{-1}{\left(1-x\right)\left(x+1\right)}$
$f\left(x\right)=\left(senx-cosx\right)\left(senx+cosx\right)+2cos2x$
$h\left(x\right)=\frac{7x^3+9}{x^4-2}$
$y=x\left(2x-3\right)\left(2x+3\right)$
$y=\left(\sin\left(x\right)+\cos\left(x\right)\right)\left(\cos\left(x\right)-\sin\left(x\right)\right)$