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Extraneous Solutions


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Extraneous Solutions.

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Problems Solved

$\log_8\left(x\right)+\log_8\left(x+2\right)=1$
$\log\left(x-3\right)-\log\left(x\right)=\log4$
$\log\left(x-2\right)+\log\left(x+1\right)=\log\left(40\right)$
$\log_6\left(2x-1\right)=2-\log_6\left(x\right)$
$\log x+\log\left(x-3\right)=1$
$-2\log_3\left(x-4\right)=\sqrt[3]{8}$
$\log_2\left(x-3\right)+\log_2\left(2x+1\right)=\log_2\left(45\right)-\log_2\left(3\right)$

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