Basic Differentiation Rules Calculator & Solver

1

Hier zeigen wir Ihnen Schritt für Schritt ein gelöstes Beispiel für grundlegende differenzierungsregeln. Diese Lösung wurde automatisch von unserem intelligenten Taschenrechner generiert:

$\frac{d}{dx}\left(\frac{x^2+3x+1}{x^2+2x+2}\right)^2$

Wenden Sie die Formel an: $\frac{d}{dx}\left(x^a\right)$$=ax^{\left(a-1\right)}\frac{d}{dx}\left(x\right)$, wobei $a=2$ und $x=\frac{x^2+3x+1}{x^2+2x+2}$

$2\left(\frac{x^2+3x+1}{x^2+2x+2}\right)^{2-1}\frac{d}{dx}\left(\frac{x^2+3x+1}{x^2+2x+2}\right)$

Wenden Sie die Formel an: $a+b$$=a+b$, wobei $a=2$, $b=-1$ und $a+b=2-1$

$2\left(\frac{x^2+3x+1}{x^2+2x+2}\right)^{1}\frac{d}{dx}\left(\frac{x^2+3x+1}{x^2+2x+2}\right)$

Wenden Sie die Formel an: $\frac{d}{dx}\left(x^a\right)$$=ax^{\left(a-1\right)}\frac{d}{dx}\left(x\right)$, wobei $a=2$ und $x=\frac{x^2+3x+1}{x^2+2x+2}$

$2\left(\frac{x^2+3x+1}{x^2+2x+2}\right)^{2-1}\frac{d}{dx}\left(\frac{x^2+3x+1}{x^2+2x+2}\right)$

Wenden Sie die Formel an: $a+b$$=a+b$, wobei $a=2$, $b=-1$ und $a+b=2-1$

$2\left(\frac{x^2+3x+1}{x^2+2x+2}\right)^{1}\frac{d}{dx}\left(\frac{x^2+3x+1}{x^2+2x+2}\right)$

2

Wenden Sie die Formel an: $\frac{d}{dx}\left(x^a\right)$$=ax^{\left(a-1\right)}\frac{d}{dx}\left(x\right)$, wobei $a=2$ und $x=\frac{x^2+3x+1}{x^2+2x+2}$

$2\left(\frac{x^2+3x+1}{x^2+2x+2}\right)^{1}\frac{d}{dx}\left(\frac{x^2+3x+1}{x^2+2x+2}\right)$

3

Wenden Sie die Formel an: $x^1$$=x$

$2\left(\frac{x^2+3x+1}{x^2+2x+2}\right)\frac{d}{dx}\left(\frac{x^2+3x+1}{x^2+2x+2}\right)$

4

Wenden Sie die Formel an: $\frac{d}{dx}\left(\frac{a}{b}\right)$$=\frac{\frac{d}{dx}\left(a\right)b-a\frac{d}{dx}\left(b\right)}{b^2}$, wobei $a=x^2+3x+1$ und $b=x^2+2x+2$

$\frac{x^2+3x+1}{x^2+2x+2}\frac{2\left(\frac{d}{dx}\left(x^2+3x+1\right)\left(x^2+2x+2\right)-\left(x^2+3x+1\right)\frac{d}{dx}\left(x^2+2x+2\right)\right)}{\left(x^2+2x+2\right)^2}$

Wenden Sie die Formel an: $\frac{a}{b}\frac{c}{f}$$=\frac{ac}{bf}$, wobei $a=x^2+3x+1$, $b=x^2+2x+2$, $c=2\left(\frac{d}{dx}\left(x^2+3x+1\right)\left(x^2+2x+2\right)-\left(x^2+3x+1\right)\frac{d}{dx}\left(x^2+2x+2\right)\right)$, $a/b=\frac{x^2+3x+1}{x^2+2x+2}$, $f=\left(x^2+2x+2\right)^2$, $c/f=\frac{2\left(\frac{d}{dx}\left(x^2+3x+1\right)\left(x^2+2x+2\right)-\left(x^2+3x+1\right)\frac{d}{dx}\left(x^2+2x+2\right)\right)}{\left(x^2+2x+2\right)^2}$ und $a/bc/f=\frac{x^2+3x+1}{x^2+2x+2}\frac{2\left(\frac{d}{dx}\left(x^2+3x+1\right)\left(x^2+2x+2\right)-\left(x^2+3x+1\right)\frac{d}{dx}\left(x^2+2x+2\right)\right)}{\left(x^2+2x+2\right)^2}$

$\frac{2\left(x^2+3x+1\right)\left(\frac{d}{dx}\left(x^2+3x+1\right)\left(x^2+2x+2\right)-\left(x^2+3x+1\right)\frac{d}{dx}\left(x^2+2x+2\right)\right)}{\left(x^2+2x+2\right)\left(x^2+2x+2\right)^2}$

5

Wenden Sie die Formel an: $\frac{a}{b}\frac{c}{f}$$=\frac{ac}{bf}$, wobei $a=x^2+3x+1$, $b=x^2+2x+2$, $c=2\left(\frac{d}{dx}\left(x^2+3x+1\right)\left(x^2+2x+2\right)-\left(x^2+3x+1\right)\frac{d}{dx}\left(x^2+2x+2\right)\right)$, $a/b=\frac{x^2+3x+1}{x^2+2x+2}$, $f=\left(x^2+2x+2\right)^2$, $c/f=\frac{2\left(\frac{d}{dx}\left(x^2+3x+1\right)\left(x^2+2x+2\right)-\left(x^2+3x+1\right)\frac{d}{dx}\left(x^2+2x+2\right)\right)}{\left(x^2+2x+2\right)^2}$ und $a/bc/f=\frac{x^2+3x+1}{x^2+2x+2}\frac{2\left(\frac{d}{dx}\left(x^2+3x+1\right)\left(x^2+2x+2\right)-\left(x^2+3x+1\right)\frac{d}{dx}\left(x^2+2x+2\right)\right)}{\left(x^2+2x+2\right)^2}$

$\frac{2\left(x^2+3x+1\right)\left(\frac{d}{dx}\left(x^2+3x+1\right)\left(x^2+2x+2\right)-\left(x^2+3x+1\right)\frac{d}{dx}\left(x^2+2x+2\right)\right)}{\left(x^2+2x+2\right)\left(x^2+2x+2\right)^2}$

Wenden Sie die Formel an: $x\cdot x^n$$=x^{\left(n+1\right)}$, wobei $x^nx=\left(x^2+2x+2\right)\left(x^2+2x+2\right)^2$, $x=x^2+2x+2$, $x^n=\left(x^2+2x+2\right)^2$ und $n=2$

$\frac{2\left(x^2+3x+1\right)\left(\frac{d}{dx}\left(x^2+3x+1\right)\left(x^2+2x+2\right)-\left(x^2+3x+1\right)\frac{d}{dx}\left(x^2+2x+2\right)\right)}{\left(x^2+2x+2\right)^{2+1}}$

Wenden Sie die Formel an: $a+b$$=a+b$, wobei $a=2$, $b=1$ und $a+b=2+1$

$\frac{2\left(x^2+3x+1\right)\left(\frac{d}{dx}\left(x^2+3x+1\right)\left(x^2+2x+2\right)-\left(x^2+3x+1\right)\frac{d}{dx}\left(x^2+2x+2\right)\right)}{\left(x^2+2x+2\right)^{3}}$

6

Wenden Sie die Formel an: $x\cdot x^n$$=x^{\left(n+1\right)}$, wobei $x^nx=\left(x^2+2x+2\right)\left(x^2+2x+2\right)^2$, $x=x^2+2x+2$, $x^n=\left(x^2+2x+2\right)^2$ und $n=2$

$\frac{2\left(x^2+3x+1\right)\left(\frac{d}{dx}\left(x^2+3x+1\right)\left(x^2+2x+2\right)-\left(x^2+3x+1\right)\frac{d}{dx}\left(x^2+2x+2\right)\right)}{\left(x^2+2x+2\right)^{3}}$

7

Wenden Sie die Formel an: $-\left(a+b\right)$$=-a-b$, wobei $a=x^2$, $b=3x+1$, $-1.0=-1$ und $a+b=x^2+3x+1$

$\frac{2\left(x^2+3x+1\right)\left(\frac{d}{dx}\left(x^2+3x+1\right)\left(x^2+2x+2\right)+\left(-x^2-\left(3x+1\right)\right)\frac{d}{dx}\left(x^2+2x+2\right)\right)}{\left(x^2+2x+2\right)^{3}}$

8

Wenden Sie die Formel an: $-\left(a+b\right)$$=-a-b$, wobei $a=3x$, $b=1$, $-1.0=-1$ und $a+b=3x+1$

$\frac{2\left(x^2+3x+1\right)\left(\frac{d}{dx}\left(x^2+3x+1\right)\left(x^2+2x+2\right)+\left(-x^2-3x-1\right)\frac{d}{dx}\left(x^2+2x+2\right)\right)}{\left(x^2+2x+2\right)^{3}}$

Wenden Sie die Formel an: $\frac{d}{dx}\left(c\right)$$=0$, wobei $c=1$

$\frac{2\left(x^2+3x+1\right)\left(\left(\frac{d}{dx}\left(x^2\right)+\frac{d}{dx}\left(3x\right)\right)\left(x^2+2x+2\right)+\left(-x^2-3x-1\right)\frac{d}{dx}\left(x^2+2x+2\right)\right)}{\left(x^2+2x+2\right)^{3}}$

9

Die Ableitung einer Summe von zwei oder mehr Funktionen ist die Summe der Ableitungen der einzelnen Funktionen

$\frac{2\left(x^2+3x+1\right)\left(\left(\frac{d}{dx}\left(x^2\right)+\frac{d}{dx}\left(3x\right)\right)\left(x^2+2x+2\right)+\left(-x^2-3x-1\right)\frac{d}{dx}\left(x^2+2x+2\right)\right)}{\left(x^2+2x+2\right)^{3}}$

Wenden Sie die Formel an: $\frac{d}{dx}\left(c\right)$$=0$, wobei $c=2$

$\frac{2\left(x^2+3x+1\right)\left(\left(\frac{d}{dx}\left(x^2\right)+\frac{d}{dx}\left(3x\right)\right)\left(x^2+2x+2\right)+\left(-x^2-3x-1\right)\left(\frac{d}{dx}\left(x^2\right)+\frac{d}{dx}\left(2x\right)\right)\right)}{\left(x^2+2x+2\right)^{3}}$

10

Die Ableitung einer Summe von zwei oder mehr Funktionen ist die Summe der Ableitungen der einzelnen Funktionen

$\frac{2\left(x^2+3x+1\right)\left(\left(\frac{d}{dx}\left(x^2\right)+\frac{d}{dx}\left(3x\right)\right)\left(x^2+2x+2\right)+\left(-x^2-3x-1\right)\left(\frac{d}{dx}\left(x^2\right)+\frac{d}{dx}\left(2x\right)\right)\right)}{\left(x^2+2x+2\right)^{3}}$

Wenden Sie die Formel an: $\frac{d}{dx}\left(cx\right)$$=c\frac{d}{dx}\left(x\right)$

$3\frac{d}{dx}\left(x\right)$

Wenden Sie die Formel an: $\frac{d}{dx}\left(x\right)$$=1$

$3$

11

Wenden Sie die Formel an: $\frac{d}{dx}\left(nx\right)$$=n\frac{d}{dx}\left(x\right)$, wobei $n=3$

$\frac{2\left(x^2+3x+1\right)\left(\left(\frac{d}{dx}\left(x^2\right)+3\frac{d}{dx}\left(x\right)\right)\left(x^2+2x+2\right)+\left(-x^2-3x-1\right)\left(\frac{d}{dx}\left(x^2\right)+\frac{d}{dx}\left(2x\right)\right)\right)}{\left(x^2+2x+2\right)^{3}}$

Wenden Sie die Formel an: $\frac{d}{dx}\left(cx\right)$$=c\frac{d}{dx}\left(x\right)$

$2\frac{d}{dx}\left(x\right)$

Wenden Sie die Formel an: $\frac{d}{dx}\left(x\right)$$=1$

$2$

12

Wenden Sie die Formel an: $\frac{d}{dx}\left(nx\right)$$=n\frac{d}{dx}\left(x\right)$, wobei $n=2$

$\frac{2\left(x^2+3x+1\right)\left(\left(\frac{d}{dx}\left(x^2\right)+3\frac{d}{dx}\left(x\right)\right)\left(x^2+2x+2\right)+\left(-x^2-3x-1\right)\left(\frac{d}{dx}\left(x^2\right)+2\frac{d}{dx}\left(x\right)\right)\right)}{\left(x^2+2x+2\right)^{3}}$

Wenden Sie die Formel an: $\frac{d}{dx}\left(x\right)$$=1$

$\frac{2\left(x^2+3x+1\right)\left(\left(\frac{d}{dx}\left(x^2\right)+3\right)\left(x^2+2x+2\right)+\left(-x^2-3x-1\right)\left(\frac{d}{dx}\left(x^2\right)+2\right)\right)}{\left(x^2+2x+2\right)^{3}}$

13

Wenden Sie die Formel an: $\frac{d}{dx}\left(x\right)$$=1$

$\frac{2\left(x^2+3x+1\right)\left(\left(\frac{d}{dx}\left(x^2\right)+3\right)\left(x^2+2x+2\right)+\left(-x^2-3x-1\right)\left(\frac{d}{dx}\left(x^2\right)+2\right)\right)}{\left(x^2+2x+2\right)^{3}}$

Wenden Sie die Formel an: $\frac{d}{dx}\left(x^a\right)$$=ax^{\left(a-1\right)}$, wobei $a=2$

$2x^{\left(2-1\right)}$

Wenden Sie die Formel an: $a+b$$=a+b$, wobei $a=2$, $b=-1$ und $a+b=2-1$

$2x$

14

Wenden Sie die Formel an: $\frac{d}{dx}\left(x^a\right)$$=ax^{\left(a-1\right)}$, wobei $a=2$

$\frac{2\left(x^2+3x+1\right)\left(\left(2x+3\right)\left(x^2+2x+2\right)+\left(-x^2-3x-1\right)\left(2x+2\right)\right)}{\left(x^2+2x+2\right)^{3}}$

Basic Differentiation Rules Calculator

Get detailed solutions to your math problems with our Basic Differentiation Rules step-by-step calculator. Practice your math skills and learn step by step with our math solver. Check out all of our online calculators here.

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Basic Differentiation Rules Calculator

Get detailed solutions to your math problems with our Basic Differentiation Rules step-by-step calculator. Practice your math skills and learn step by step with our math solver. Check out all of our online calculators here.

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