Prove $\left(x\sin\left(x\right)-y\cos\left(x\right)\right)^2+\left(x\cos\left(x\right)+y\sin\left(x\right)\right)^2=x^2+y^2$

Step-by-step Solution

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Final answer to the problem

true

Step-by-step Solution

How should I solve this problem?

  • Prove from LHS (left-hand side)
  • Prove from RHS (right-hand side)
  • Express everything into Sine and Cosine
  • Exact Differential Equation
  • Linear Differential Equation
  • Separable Differential Equation
  • Homogeneous Differential Equation
  • Integrate by partial fractions
  • Product of Binomials with Common Term
  • FOIL Method
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Starting from the left-hand side (LHS) of the identity

Learn how to solve differential calculus problems step by step online.

$\left(x\sin\left(x\right)-y\cos\left(x\right)\right)^2+\left(x\cos\left(x\right)+y\sin\left(x\right)\right)^2$

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Learn how to solve differential calculus problems step by step online. Prove (xsin(x)-ycos(x))^2+(xcos(x)+ysin(x))^2=x^2+y^2. Starting from the left-hand side (LHS) of the identity. A binomial squared (difference) is equal to the square of the first term, minus the double product of the first by the second, plus the square of the second term. In other words: (a-b)^2=a^2-2ab+b^2. The power of a product is equal to the product of it's factors raised to the same power. Using the sine double-angle identity: \sin\left(2\theta\right)=2\sin\left(\theta\right)\cos\left(\theta\right).

Final answer to the problem

true

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Function Plot

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Main Topic: Differential Calculus

The derivative of a function of a real variable measures the sensitivity to change of a quantity (a function value or dependent variable) which is determined by another quantity (the independent variable). Derivatives are a fundamental tool of calculus.

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