Final answer to the problem
$p\left(x\right)=\left(x+2\right)^2+\left(x-2\right)^2-x^2+9$
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Step-by-step Solution
How should I solve this problem?
- Choose an option
- Write in simplest form
- Solve by quadratic formula (general formula)
- Find the derivative using the definition
- Simplify
- Find the integral
- Find the derivative
- Factor
- Factor by completing the square
- Find the roots
- Load more...
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1
The sum of two terms multiplied by their difference is equal to the square of the first term minus the square of the second term. In other words: $(a+b)(a-b)=a^2-b^2$.
Learn how to solve factor by difference of squares problems step by step online.
$p\left(x\right)=\left(x+2\right)^2+\left(x-2\right)^2-\left(x^2-9\right)$
Learn how to solve factor by difference of squares problems step by step online. Simplify the expression p(x)=(x+2)^2+(x-2)^2-(x-3)(x+3). The sum of two terms multiplied by their difference is equal to the square of the first term minus the square of the second term. In other words: (a+b)(a-b)=a^2-b^2.. Simplify the product -(x^2-9).
Final answer to the problem
$p\left(x\right)=\left(x+2\right)^2+\left(x-2\right)^2-x^2+9$
