Final answer to the problem
$\frac{\sqrt{2-a}\left(2-\sqrt{2-a}\right)}{2+a}$
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Step-by-step Solution
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- Integrate by partial fractions
- Product of Binomials with Common Term
- FOIL Method
- Integrate by substitution
- Integrate by parts
- Integrate using tabular integration
- Integrate by trigonometric substitution
- Weierstrass Substitution
- Prove from LHS (left-hand side)
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1
Multiply and divide the fraction $\frac{\sqrt{2-a}}{2+\sqrt{2-a}}$ by the conjugate of it's denominator $2+\sqrt{2-a}$
$\frac{\sqrt{2-a}}{2+\sqrt{2-a}}\frac{2-\sqrt{2-a}}{2-\sqrt{2-a}}$
Learn how to solve rationalisation problems step by step online.
$\frac{\sqrt{2-a}}{2+\sqrt{2-a}}\frac{2-\sqrt{2-a}}{2-\sqrt{2-a}}$
Learn how to solve rationalisation problems step by step online. Rationalize and simplify the expression ((2-a)^(1/2))/(2+(2-a)^(1/2)). Multiply and divide the fraction \frac{\sqrt{2-a}}{2+\sqrt{2-a}} by the conjugate of it's denominator 2+\sqrt{2-a}. Multiplying fractions \frac{\sqrt{2-a}}{2+\sqrt{2-a}} \times \frac{2-\sqrt{2-a}}{2-\sqrt{2-a}}. Solve the product of difference of squares \left(2+\sqrt{2-a}\right)\left(2-\sqrt{2-a}\right).
Final answer to the problem
$\frac{\sqrt{2-a}\left(2-\sqrt{2-a}\right)}{2+a}$
