Find the limit of $\sqrt{x^2-9x+1}-x$ as $x$ approaches $\infty $

Step-by-step Solution

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Final answer to the problem

$-\frac{9}{2}$
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Step-by-step Solution

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  • Solve using L'Hôpital's rule
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  • Solve the limit using factorization
  • Solve the limit using rationalization
  • Integrate by partial fractions
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1

Applying rationalisation

$\lim_{x\to\infty }\left(\left(\sqrt{x^2-9x+1}-x\right)\frac{\sqrt{x^2-9x+1}+x}{\sqrt{x^2-9x+1}+x}\right)$

Learn how to solve limits to infinity problems step by step online.

$\lim_{x\to\infty }\left(\left(\sqrt{x^2-9x+1}-x\right)\frac{\sqrt{x^2-9x+1}+x}{\sqrt{x^2-9x+1}+x}\right)$

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Learn how to solve limits to infinity problems step by step online. Find the limit of (x^2-9x+1)^(1/2)-x as x approaches infinity. Applying rationalisation. Multiply and simplify the expression within the limit. Cancel like terms x^2 and -x^2. As it's an indeterminate limit of type \frac{\infty}{\infty}, divide both numerator and denominator by the term of the denominator that tends more quickly to infinity (the term that, evaluated at a large value, approaches infinity faster). In this case, that term is .

Final answer to the problem

$-\frac{9}{2}$

Exact Numeric Answer

$-4.5$

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Function Plot

Plotting: $\sqrt{x^2-9x+1}-x$

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9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

How to improve your answer:

Main Topic: Limits to Infinity

The limit of a function f(x) when x tends to infinity is the value that the function takes as the value of x grows indefinitely.

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