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Factor the difference of squares $x^4-2$ as the product of two bynomials: $a^2-b^2=(a+b)(a-b)$
Learn how to solve factor by difference of squares problems step by step online.
$h\left(x\right)=\frac{7x^3+9}{-\left(\sqrt{2}+x^2\right)\left(\sqrt[4]{2}+x\right)\left(\sqrt[4]{2}-x\right)}$
Learn how to solve factor by difference of squares problems step by step online. Simplify the expression h(x)=(7x^3+9)/(x^4-2). Factor the difference of squares x^4-2 as the product of two bynomials: a^2-b^2=(a+b)(a-b). The sum of two terms multiplied by their difference is equal to the square of the first term minus the square of the second term. In other words: (a+b)(a-b)=a^2-b^2.. Simplify \left(\sqrt[4]{2}\right)^2 using the power of a power property: \left(a^m\right)^n=a^{m\cdot n}. In the expression, m equals \frac{1}{4} and n equals 2. Solve the product of difference of squares -\left(\sqrt{2}+x^2\right)\left(\sqrt{2}-x^2\right).
