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Solve the logarithmic equation $\log \left(x-2\right)+\log \left(x+1\right)=\log \left(40\right)$

Step-by-step Solution

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Solution

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Final answer to the problem

$x=7$
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Step-by-step Solution

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The sum of two logarithms of the same base is equal to the logarithm of the product of the arguments

Learn how to solve logarithmic equations problems step by step online.

$\log \left(\left(x-2\right)\left(x+1\right)\right)=\log \left(40\right)$

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Learn how to solve logarithmic equations problems step by step online. Solve the logarithmic equation log(x+-2)+log(x+1)=log(40). The sum of two logarithms of the same base is equal to the logarithm of the product of the arguments. For two logarithms of the same base to be equal, their arguments must be equal. In other words, if \log(a)=\log(b) then a must equal b. Multiplying polynomials x-2 and x+1. Multiply the single term x by each term of the polynomial \left(x-2\right).

Final answer to the problem

$x=7$

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Function Plot

Plotting: $\log \left(x-2\right)+\log \left(x+1\right)-\log \left(40\right)$

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0
a
b
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d
f
g
m
n
u
v
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x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
◻2
◻◻
√◻
√

◻√◻
◻√
∞
e
π
ln
log
log◻
lim
d/dx
D□x
∫
∫◻
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

How to improve your answer:

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Main Topic: Logarithmic Equations

Are those equations in which the unknown variable appears within a logarithm.

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