Solve the quadratic equation $3\left(2x-1\right)^2+5\left(x+4\right)-3=\left(3x+4\right)^2+4x-5$

Step-by-step Solution

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Final answer to the problem

$x=\frac{35+\sqrt{1117}}{6},\:x=\frac{35-\sqrt{1117}}{6}$
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Step-by-step Solution

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Multiply the single term $5$ by each term of the polynomial $\left(x+4\right)$

$3\left(2x-1\right)^2+5x+17=\left(3x+4\right)^2+4x-5$

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$3\left(2x-1\right)^2+5x+17=\left(3x+4\right)^2+4x-5$

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Learn how to solve problems step by step online. Solve the quadratic equation 3(2x-1)^2+5(x+4)+-3=(3x+4)^2+4x+-5. Multiply the single term 5 by each term of the polynomial \left(x+4\right). Move everything to the left hand side of the equation. Add the values 17 and 5. Combining like terms 5x and -4x.

Final answer to the problem

$x=\frac{35+\sqrt{1117}}{6},\:x=\frac{35-\sqrt{1117}}{6}$

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Function Plot

Plotting: $3\left(2x-1\right)^2+5\left(x+4\right)-3-\left(3x+4\right)^2-4x+5$

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7
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9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

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