Solve the product $\left(x^2-3\right)\left(-3-x^2\right)$

Step-by-step Solution

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Final answer to the problem

$-x^{4}+9$
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Step-by-step Solution

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  • Product of Binomials with Common Term
  • FOIL Method
  • Find the integral
  • Find the derivative
  • Factor
  • Integrate by partial fractions
  • Integrate by substitution
  • Integrate by parts
  • Integrate using tabular integration
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1

Multiply the single term $-3-x^2$ by each term of the polynomial $\left(x^2-3\right)$

Learn how to solve definite integrals problems step by step online.

$x^2\left(-3-x^2\right)-3\left(-3-x^2\right)$

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Learn how to solve definite integrals problems step by step online. Solve the product (x^2-3)(-3-x^2). Multiply the single term -3-x^2 by each term of the polynomial \left(x^2-3\right). Multiply the single term x^2 by each term of the polynomial \left(-3-x^2\right). When multiplying exponents with same base we can add the exponents. Multiply the single term -3 by each term of the polynomial \left(-3-x^2\right).

Final answer to the problem

$-x^{4}+9$

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Function Plot

Plotting: $-x^{4}+9$

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Go!
1
2
3
4
5
6
7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

How to improve your answer:

Main Topic: Definite Integrals

Given a function f(x) and the interval [a,b], the definite integral is equal to the area that is bounded by the graph of f(x), the x-axis and the vertical lines x=a and x=b

Used Formulas

See formulas (1)

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