Final answer to the problem
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- Solve by quadratic formula (general formula)
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The sum of two terms multiplied by their difference is equal to the square of the first term minus the square of the second term. In other words: $(a+b)(a-b)=a^2-b^2$.
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$f\left(x\right)=\sin\left(x\right)^2-\cos\left(x\right)^2+2\cos\left(x\right)^2$
Learn how to solve algebraic expressions problems step by step online. Simplify the expression f(x)=(sin(x)-cos(x))(sin(x)+cos(x))+2cos(x)^2. The sum of two terms multiplied by their difference is equal to the square of the first term minus the square of the second term. In other words: (a+b)(a-b)=a^2-b^2.. Combining like terms -\cos\left(x\right)^2 and 2\cos\left(x\right)^2. Applying the pythagorean identity: \sin^2\left(\theta\right)+\cos^2\left(\theta\right)=1.