Prove the trigonometric identity $\frac{1}{1-\sin\left(x\right)}+\frac{-1}{1+\sin\left(x\right)}=2\tan\left(x\right)\sec\left(x\right)$

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Trigonometric Identities

$1-\sin\left(\theta \right)^2=\cos\left(\theta \right)^2$
· Reciprocal identity of cosine and secant
$\cos\left(\theta \right)=\frac{1}{\sec\left(\theta \right)}$

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Main Topic: Factor by Difference of Squares

The difference of two squares is a squared number subtracted from another squared number. Every difference of squares may be factored according to the identity a^2-b^2=(a+b)(a-b) in elementary algebra.

Used Formulas

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