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Solve the product $\left(a^{\left(x+1\right)}- 26^{\left(x-1\right)}\right)\left(26^{\left(x-1\right)}+a^{\left(x+1\right)}\right)$

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 Solution

 Videos

Algebra 2 - Solving a factored quadratic equation using the zero product property, -x(3x + 5) = 0

https://www.youtube.com/watch?v=3on6rsKoK_k

Algebra 2 - How to find the solutions of a quadratic using the quadratic formula, 4x^2 + x = 3

https://www.youtube.com/watch?v=ZQu6QjBgXS8

Tutorial - How to solve by factoing using a perfect square trinomial y=20x+x^2+100

https://www.youtube.com/watch?v=VV8EOcSVZX4

Tutorial - Solve using the perfect square trinomial factoring technique y=4x^2+16x+16

https://www.youtube.com/watch?v=Kl5DA2U7vJU

Tutorial - Solve by factoring when a perfect square 0=x^2+6x+9

https://www.youtube.com/watch?v=F7O02LqPQp0

Find all the Zeros by Factoring a Polynomial to the 4th Power

https://www.youtube.com/watch?v=8mDBQvHuP9E

 Function Plot

Plotting: $a^{\left(2x+2\right)}- 26^{\left(2x-2\right)}$

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1

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5

6

7

8

9

0



a

b

c

d

f

g

m

n

u

v

w

x

y

z

.

(◻)

+

-

×

◻/◻

/

÷

◻²

◻^◻

√◻

√

^◻√◻

^◻√

∞

e

π

ln

log

log_◻

lim

d/dx

D^□_x

∫

∫^◻

|◻|

θ

=

>

<

>=

<=

sin

cos

tan

cot

sec

csc

asin

acos

atan

acot

asec

acsc

sinh

cosh

tanh

coth

sech

csch

asinh

acosh

atanh

acoth

asech

acsch

 How to improve your answer:

 Main Topic: Factor by Difference of Squares

The difference of two squares is a squared number subtracted from another squared number. Every difference of squares may be factored according to the identity a^2-b^2=(a+b)(a-b) in elementary algebra.

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