Find the limit of $\frac{\sqrt[3]{6x^2-x^3}+x}{2.1}$ as $x$ approaches $\infty $

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Plotting: $\frac{\sqrt[3]{6x^2-x^3}+x}{2.1}$

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0
a
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f
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m
n
u
v
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x
y
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.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

How to improve your answer:

Main Topic: Limits to Infinity

The limit of a function f(x) when x tends to infinity is the value that the function takes as the value of x grows indefinitely.

Used Formulas

See formulas (2)

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