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Find the limit of $\frac{-e^{2\cdot 2^{0.5}x}}{1-e^{2\cdot 2^{0.5}x}}$ as $x$ approaches $\infty $

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 Solution

 Videos

Calculus - Evaluating a limit at infinity horizontal asymptote, lim(x tends to infinity)(2x-1)/(x+1)

https://www.youtube.com/watch?v=miPOf5lXfpw

Tutorial - Condensing logarithmic expressions ex 11, 1/2(3log2(x)-2 log2(z))

https://www.youtube.com/watch?v=doNh13E4XBo

Limit of (sin x)/x as x approaches 0

https://www.youtube.com/watch?v=5xitzTutKqM

Finding the x intercepts of a quadratic equation - Free Math Help

https://www.youtube.com/watch?v=KMyKCJrjZZI

Derivatives of sec(x) and csc(x) | Derivative rules | AP Calculus AB | Khan Academy

https://www.youtube.com/watch?v=TDJ5nXWEkWM

Finding zeros of polynomials (1 of 2) | Mathematics III | High School Math | Khan Academy

https://www.youtube.com/watch?v=x9lb_frpkH0

 Function Plot

Plotting: $\frac{-e^{2\cdot 2^{0.5}x}}{1-e^{2\cdot 2^{0.5}x}}$

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1

2

3

4

5

6

7

8

9

0



a

b

c

d

f

g

m

n

u

v

w

x

y

z

.

(◻)

+

-

×

◻/◻

/

÷

◻²

◻^◻

√◻

√

^◻√◻

^◻√

∞

e

π

ln

log

log_◻

lim

d/dx

D^□_x

∫

∫^◻

|◻|

θ

=

>

<

>=

<=

sin

cos

tan

cot

sec

csc

asin

acos

atan

acot

asec

acsc

sinh

cosh

tanh

coth

sech

csch

asinh

acosh

atanh

acoth

asech

acsch

 How to improve your answer:

 Main Topic: Special Products

Special products is the multiplication of algebraic expressions that follow certain rules and patterns, so you can predict the result without necessarily doing the multiplication.

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