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Express the numbers in the equation as logarithms of base $5$
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$\log_{5}\left(x\right)+\log_{5}\left(4x-1\right)=\log_{5}\left(5^{1}\right)$
Learn how to solve problems step by step online. Solve the logarithmic equation log5(x)+log5(4*x+-1)=1. Express the numbers in the equation as logarithms of base 5. Any expression to the power of 1 is equal to that same expression. The sum of two logarithms of the same base is equal to the logarithm of the product of the arguments. For two logarithms of the same base to be equal, their arguments must be equal. In other words, if \log(a)=\log(b) then a must equal b.