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Simplify the equation $k=\sqrt{\left(x+13\right)\left(13-x\right)+\left(5+x\right)\left(x-5\right)}$

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 Solution

 Videos

Algebra 2 - Multiplying two exponents with rational powers, then simplifying, 2x^(2/5) . 6x^(1/4)

https://www.youtube.com/watch?v=ITQM50h5BlY

Tutorial - Solving logarithmic equations ex 10, log(2x)+log(x-5)=2

https://www.youtube.com/watch?v=fzjoQXBd0uU

Algebra 2 - using the square root method to solve a quadratic equation 4x^2 - 4x + 1 = 9

https://www.youtube.com/watch?v=90FQ2oLoEEQ

Tutorial - Solving a rational Equation ex2, 1/x + x/2 = (x+4)/ 2x

https://www.youtube.com/watch?v=a49VWDDgsMk

Graphing solutions to two-variable linear equations example 1 | Algebra I | Khan Academy

https://www.youtube.com/watch?v=86NwKBcOlow

Solving for x in an equation using addition and division

https://www.youtube.com/watch?v=M2uz08i7Ggs

 Function Plot

Plotting: $k-\sqrt{\left(x+13\right)\left(13-x\right)+\left(5+x\right)\left(x-5\right)}$

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1

2

3

4

5

6

7

8

9

0



a

b

c

d

f

g

m

n

u

v

w

x

y

z

.

(◻)

+

-

×

◻/◻

/

÷

◻²

◻^◻

√◻

√

^◻√◻

^◻√

∞

e

π

ln

log

log_◻

lim

d/dx

D^□_x

∫

∫^◻

|◻|

θ

=

>

<

>=

<=

sin

cos

tan

cot

sec

csc

asin

acos

atan

acot

asec

acsc

sinh

cosh

tanh

coth

sech

csch

asinh

acosh

atanh

acoth

asech

acsch

 How to improve your answer:

 Main Topic: Two-variable linear equations

Algebraic equations that have two distinct variables.

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