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Simplify the expression $p\left(x\right)=\left(x+2\right)^2+\left(x-2\right)^2-\left(x-3\right)\left(x+3\right)$

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 Solution

 Videos

Algebra 2 - Simplifying a radical expression by multiplying by conjugate, sqrt(x) / (sqrt(x) + 3)

https://www.youtube.com/watch?v=S1A48ASMoYU

Algebra 2 - How to find the solutions of a quadratic using the quadratic formula, 4x^2 + x = 3

https://www.youtube.com/watch?v=ZQu6QjBgXS8

Tutorial - Simplify a trigonometric expression by factoring ex 26, 2(cosx)^2 + cosx - 3

https://www.youtube.com/watch?v=X35--yiv4Ms

Pre-Calculus - How to simplify a trigonometric expression by squaring a binomial (sin(x)+cos(x))^2

https://www.youtube.com/watch?v=e5IczuZxvVI

Polynomial special products: difference of squares | Algebra 2 | Khan Academy

https://www.youtube.com/watch?v=uNweU6I4Icw

Algebra 2 - Learn to solve a rational equation by multiplying by the LCD (15/x)+((9x-7)/(x+2))=9

https://www.youtube.com/watch?v=BMSmvkWcVTU

 Function Plot

Plotting: $p\left(x\right)-\left(x+2\right)^2-\left(x-2\right)^2+\left(x-3\right)\left(x+3\right)$

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1

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4

5

6

7

8

9

0



a

b

c

d

f

g

m

n

u

v

w

x

y

z

.

(◻)

+

-

×

◻/◻

/

÷

◻²

◻^◻

√◻

√

^◻√◻

^◻√

∞

e

π

ln

log

log_◻

lim

d/dx

D^□_x

∫

∫^◻

|◻|

θ

=

>

<

>=

<=

sin

cos

tan

cot

sec

csc

asin

acos

atan

acot

asec

acsc

sinh

cosh

tanh

coth

sech

csch

asinh

acosh

atanh

acoth

asech

acsch

 How to improve your answer:

 Main Topic: Factor by Difference of Squares

The difference of two squares is a squared number subtracted from another squared number. Every difference of squares may be factored according to the identity a^2-b^2=(a+b)(a-b) in elementary algebra.

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