Exercise
$\left(\frac{1}{3}a^2+\frac{2}{9}b\right)\left(\frac{1}{3}a^2-\frac{2}{9}b\right)$
Step-by-step Solution
Learn how to solve special products problems step by step online. Simplify the product of conjugate binomials (1/3a^2+2/9b)(1/3a^2-2/9b). The sum of two terms multiplied by their difference is equal to the square of the first term minus the square of the second term. In other words: (a+b)(a-b)=a^2-b^2.. The power of a product is equal to the product of it's factors raised to the same power. . Calculate the power \left(\frac{1}{3}\right)^2.
Simplify the product of conjugate binomials (1/3a^2+2/9b)(1/3a^2-2/9b)
Final answer to the exercise
$\frac{1}{9}a^{4}-\frac{4}{81}b^2$