Exercise
$\left(\frac{x^3}{2}-\frac{2y}{3}\right)\left(\frac{x^3}{2}+\frac{2y}{3}\right)$
Step-by-step Solution
Learn how to solve special products problems step by step online. Simplify the product of conjugate binomials ((x^3)/2+(-2y)/3)((x^3)/2+(2y)/3). The sum of two terms multiplied by their difference is equal to the square of the first term minus the square of the second term. In other words: (a+b)(a-b)=a^2-b^2.. The power of a quotient is equal to the quotient of the power of the numerator and denominator: \displaystyle\left(\frac{a}{b}\right)^n=\frac{a^n}{b^n}. Combine \frac{x^{6}}{4}-\left(\frac{2y}{3}\right)^2 in a single fraction. The power of a quotient is equal to the quotient of the power of the numerator and denominator: \displaystyle\left(\frac{a}{b}\right)^n=\frac{a^n}{b^n}.
Simplify the product of conjugate binomials ((x^3)/2+(-2y)/3)((x^3)/2+(2y)/3)
Final answer to the exercise
$\frac{x^{6}-\frac{16}{9}y^2}{4}$